Which one of the following statements is correct when SO2 is passed through acidified K2Cr2O7 solution ?

Question

Which one of the following statements is correct when SO2 is passed through acidified K2Cr2O7 solution ? (A) The solution is decolourized (B) SO2 is reduced (C) Green Cr2(SO4)3 is formed (D) The solution turns blue

Tardigrade Admin · Accepted Answer

Acidified K2Cr2O7 oxidizes SO2 to green colour Cr2(SO4)3 K2Cr2O7 + 3SO2 + H2 SO4 arrow K1SO4 + underset text greenCr2(SO4)3 + H2O

Q. Which one of the following statements is correct when $S O_{2}$ is passed through acidified $K_{2} C r_{2} O_{7}$ solution ?

The solution is decolourized

$S O_{2}$ is reduced

Green $C r_{2} (S O_{4})_{3}$ is formed

The solution turns blue

Acidified $K_{2} C r_{2} O_{7}$ oxidizes $S O_{2}$ to green colour $C r_{2} (S O_{4})_{3}$
$K_{2} C r_{2} O_{7} + 3 S O_{2} + H_{2} S O_{4} \to K_{1} S O_{4} + green C r_{2} (S O_{4})_{3} + H_{2} O$

Q. Which one of the following statements is correct when SO2​ is passed through acidified K2​Cr2​O7​ solution ?

The solution is decolourized

SO2​ is reduced

Green Cr2​(SO4​)3​ is formed

The solution turns blue

Acidified K2​Cr2​O7​ oxidizes SO2​ to green colour Cr2​(SO4​)3​ K2​Cr2​O7​+3SO2​+H2​SO4​→K1​SO4​+ greenCr2​(SO4​)3​​+H2​O

Q. Which one of the following statements is correct when $S O_{2}$ is passed through acidified $K_{2} C r_{2} O_{7}$ solution ?

$S O_{2}$ is reduced

Green $C r_{2} (S O_{4})_{3}$ is formed

Acidified $K_{2} C r_{2} O_{7}$ oxidizes $S O_{2}$ to green colour $C r_{2} (S O_{4})_{3}$
$K_{2} C r_{2} O_{7} + 3 S O_{2} + H_{2} S O_{4} \to K_{1} S O_{4} + green C r_{2} (S O_{4})_{3} + H_{2} O$