Which one of the following set of quantum numbers is not possible for electron in the ground state of an atom with atomic number 19?

Question

Which one of the following set of quantum numbers is not possible for electron in the ground state of an atom with atomic number 19? (A)  n=2, l=0, m=0  (B)  n=2, l=1, m=0  (C)  n=3, l=1, m=-1  (D)  n=3, l=2, m=+ 2

Tardigrade Admin · Accepted Answer

K(Z=19):1 s2, 2s22p6,3s23p6,4s1 In the ground state, the value of l can be either zero or one. Hence, the set of quantum numbers i.e., ( n=3, text l=2, text m=+2 ) cannot be possible in the ground state of the atom.

Q. Which one of the following set of quantum numbers is not possible for electron in the ground state of an atom with atomic number 19?

$n = 2, l = 0, m = 0$

$n = 2, l = 1, m = 0$

$n = 3, l = 1, m = - 1$

$n = 3, l = 2, m = + 2$

$K (Z = 19) : 1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6}, 4 s^{1}$ In the ground state, the value of $l$ can be either zero or one. Hence, the set of quantum numbers i.e., $(n = 3, l = 2, m = + 2)$ cannot be possible in the ground state of the atom.

Q. Which one of the following set of quantum numbers is not possible for electron in the ground state of an atom with atomic number 19?

n=2,l=0,m=0

n=2,l=1,m=0

n=3,l=1,m=−1

n=3,l=2,m=+2

K(Z=19):1s2,2s22p6,3s23p6,4s1 In the ground state, the value of l can be either zero or one. Hence, the set of quantum numbers i.e., (n=3,l=2,m=+2) cannot be possible in the ground state of the atom.

$n = 2, l = 0, m = 0$

$n = 2, l = 1, m = 0$

$n = 3, l = 1, m = - 1$

$n = 3, l = 2, m = + 2$

$K (Z = 19) : 1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6}, 4 s^{1}$ In the ground state, the value of $l$ can be either zero or one. Hence, the set of quantum numbers i.e., $(n = 3, l = 2, m = + 2)$ cannot be possible in the ground state of the atom.