Which one of the following sequences represents the correct increasing order of bond angles in the given molecules ?

Question

Which one of the following sequences represents the correct increasing order of bond angles in the given molecules ? (A) H2O < OF2 < OCl2 < ClO2 (B) OCl2 < ClO2 < H2O < OF2 (C) OF2 < H2O < OCl2 < ClO2  (D)  ClO2 < OF2 < OCl2 < H2O

Tardigrade Admin · Accepted Answer

H2O is sp3 hybridised with bond angle 104.5° due to presence of two lone pairs. OF2 has structure similar to H2O with bond angle 103° due to higher electronegativity of fluorine. OCl2 also has similar structure with bond angle 111° because of steric crowding of two chlorine atoms. However ClO2 has π- bond character with an odd electron so that bond angle is 118°. Thus four compounds can be arranged in order of their bond angle as

Q. Which one of the following sequences represents the correct increasing order of bond angles in the given molecules ?

$H_{2} O < O F_{2} < OC l_{2} < Cl O_{2}$

$OC l_{2} < Cl O_{2} < H_{2} O < O F_{2}$

$O F_{2} < H_{2} O < OC l_{2} < Cl O_{2}$

$Cl O_{2} < O F_{2} < OC l_{2} < H_{2} O$

Q. Which one of the following sequences represents the correct increasing order of bond angles in the given molecules ?

H2​O<OF2​<OCl2​<ClO2​

OCl2​<ClO2​<H2​O<OF2​

OF2​<H2​O<OCl2​<ClO2​

ClO2​<OF2​<OCl2​<H2​O

$H_{2} O < O F_{2} < OC l_{2} < Cl O_{2}$

$OC l_{2} < Cl O_{2} < H_{2} O < O F_{2}$

$O F_{2} < H_{2} O < OC l_{2} < Cl O_{2}$

$Cl O_{2} < O F_{2} < OC l_{2} < H_{2} O$