Which one of the following is a correct set with respect to molecule, hybridization and shape?

Question

Which one of the following is a correct set with respect to molecule, hybridization and shape? (A)  BeCl2,sp2, linear (B)  BeCl2, text sp2, triangular planar (C)  BCl3, text sp2, triangular planar (D) B BCl3,sp3, tetrahedral

Tardigrade Admin · Accepted Answer

textBeC textl text2 has only 2 bond pair electrons. So, its hybridisation will be sp and structure is linear. In textBC textl text3 there is 3 bond pair of electrons. So, its hybridisation is sp2 and bond angle is text12 text0 texto and its shape is trigonal planar.

Q. Which one of the following is a correct set with respect to molecule, hybridization and shape?

$B e C l_{2}, s p^{2},$ linear

$B e C l_{2}, s p^{2},$ triangular planar

$BC l_{3}, s p^{2},$ triangular planar

B $BC l_{3}, s p^{3},$ tetrahedral

$BeC l_{2}$ has only 2 bond pair electrons. So, its hybridisation will be sp and structure is linear. In $BC l_{3}$ there is 3 bond pair of electrons. So, its hybridisation is $s p^{2}$ and bond angle is $12 0^{o}$ and its shape is trigonal planar.

Q. Which one of the following is a correct set with respect to molecule, hybridization and shape?

BeCl2​,sp2, linear

BeCl2​,sp2, triangular planar

BCl3​,sp2, triangular planar

B BCl3​,sp3, tetrahedral

BeCl2​ has only 2 bond pair electrons. So, its hybridisation will be sp and structure is linear. In BCl3​ there is 3 bond pair of electrons. So, its hybridisation is sp2 and bond angle is 120o and its shape is trigonal planar.

$B e C l_{2}, s p^{2},$ linear

$B e C l_{2}, s p^{2},$ triangular planar

$BC l_{3}, s p^{2},$ triangular planar

B $BC l_{3}, s p^{3},$ tetrahedral

$BeC l_{2}$ has only 2 bond pair electrons. So, its hybridisation will be sp and structure is linear. In $BC l_{3}$ there is 3 bond pair of electrons. So, its hybridisation is $s p^{2}$ and bond angle is $12 0^{o}$ and its shape is trigonal planar.