Which one of the following is a correct set?

Question

Which one of the following is a correct set? (A) H2O, sp3 , angular (B) H2O, sp2 , linear (C) NH4+, dsp2, square planar (D) CH4, dsp2, tetrahedral

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-msaikqcx9vxz4wim.jpg" /> H2O molecule is having two bond pairs and two lone pairs. Hence, textH2 textO has texts textp3 -hybridisation and is angular. NH4+andCH4 molecule are having all four bond pairs, hence, they have sp3 -hybridisation and are tetrahedral.

Q. Which one of the following is a correct set?

$H_{2} O, s p^{3}$ , angular

$H_{2} O, s p^{2}$ , linear

$N H_{4}^{+}, d s p^{2},$ square planar

$C H_{4}, d s p^{2},$ tetrahedral

$H_{2} O$ molecule is having two bond pairs and two lone pairs. Hence, $H_{2} O$ has $s p^{3}$ -hybridisation and is angular.
$N H_{4}^{+} an d C H_{4}$ molecule are having all four bond pairs, hence, they have $s p^{3}$ -hybridisation and are tetrahedral.

Q. Which one of the following is a correct set?

H2​O,sp3 , angular

H2​O,sp2 , linear

NH4+​,dsp2, square planar

CH4​,dsp2, tetrahedral

H2​O molecule is having two bond pairs and two lone pairs. Hence, H2​O has sp3 -hybridisation and is angular. NH4+​andCH4​ molecule are having all four bond pairs, hence, they have sp3 -hybridisation and are tetrahedral.

$H_{2} O, s p^{3}$ , angular

$H_{2} O, s p^{2}$ , linear

$N H_{4}^{+}, d s p^{2},$ square planar

$C H_{4}, d s p^{2},$ tetrahedral

$H_{2} O$ molecule is having two bond pairs and two lone pairs. Hence, $H_{2} O$ has $s p^{3}$ -hybridisation and is angular.
$N H_{4}^{+} an d C H_{4}$ molecule are having all four bond pairs, hence, they have $s p^{3}$ -hybridisation and are tetrahedral.