Question

Which one of the following has the smallest bond angle ?

• A. $N{H}_3$
• B. $Be{F}_2$
• C. $H_{2}O$
• D. $C{H}_4$

Answer 1

Answer: (C)

Hybridisation involved in $N{H}_3$ is $s{p}^3$ with one lone pair, in $Be{F}_2$ is $s{p}^2$ with no lone pair, in $H_{2}O$ is $s{p}^3$ with two lone pairs, in $C{H}_4$ is $s{p}^3$ with no lone pair, in $S{O}_2$ is $s{p}^1$ with one lone pair. Therefore, least bond angle is $H_{2}O$ (= 104-5${}^{\circ }$).