Which one of the following equations represents parametrically, parabolic profile?

Question

Which one of the following equations represents parametrically, parabolic profile? (A) x=3 cos t ; y=4 sin t (B) x2-2=- cos t ; y=4 cos 2 (t/2) (C) √ x = tan t ; √ y = sec t (D) x=√1- sin t ; y= sin (t/2)+ cos (t/2)

Tardigrade Admin · Accepted Answer

Correct answer is (b) x2-2=- cos t ; y=4 cos 2 (t/2)

Q. Which one of the following equations represents parametrically, parabolic profile?

$x = 3 cos t; y = 4 sin t$

$x^{2} - 2 = - cos t; y = 4 cos^{2} \frac{t}{2}$

$x = tan t; y = sec t$

$x = 1 - sin t; y = sin \frac{t}{2} + cos \frac{t}{2}$

Correct answer is (b) $x^{2} - 2 = - cos t; y = 4 cos^{2} \frac{t}{2}$

Q. Which one of the following equations represents parametrically, parabolic profile?

x=3cost;y=4sint

x2−2=−cost;y=4cos22t​

x​=tant;y​=sect

x=1−sint​;y=sin2t​+cos2t​

Correct answer is (b) x2−2=−cost;y=4cos22t​

$x = 3 cos t; y = 4 sin t$

$x^{2} - 2 = - cos t; y = 4 cos^{2} \frac{t}{2}$

$x = tan t; y = sec t$

$x = 1 - sin t; y = sin \frac{t}{2} + cos \frac{t}{2}$

Correct answer is (b) $x^{2} - 2 = - cos t; y = 4 cos^{2} \frac{t}{2}$