Which of the functions defined below are one-one function(s)?

Question

Which of the functions defined below are one-one function(s)? (A) f(x)=(x+1),(x ≥-1) (B) g(x)=x+(1 / x)(x>0) (C) h(x)=x2+4 x-5,(x>0) (D) f(x)=e-x,(x ≥ 0)

Tardigrade Admin · Accepted Answer

(x) = x + 1 f(x) = x+1 for x >-1

g(x)=x+(1/x) for x>0

Many-one function

Q. Which of the functions defined below are one-one function(s)?

$f (x) = (x + 1), (x \geq - 1)$

$g (x) = x + (1/ x) (x > 0)$

$h (x) = x^{2} + 4 x - 5, (x > 0)$

$f (x) = e^{- x}, (x \geq 0)$

$(x) = x + 1$
$f (x) = x + 1$ for $x > - 1$

$g (x) = x + \frac{1}{x}$ for $x > 0$

Many-one function

Q. Which of the functions defined below are one-one function(s)?

f(x)=(x+1),(x≥−1)

g(x)=x+(1/x)(x>0)

h(x)=x2+4x−5,(x>0)

f(x)=e−x,(x≥0)

(x)=x+1 f(x)=x+1 for x>−1 g(x)=x+x1​ for x>0 Many-one function

$f (x) = (x + 1), (x \geq - 1)$

$g (x) = x + (1/ x) (x > 0)$

$h (x) = x^{2} + 4 x - 5, (x > 0)$

$f (x) = e^{- x}, (x \geq 0)$

$(x) = x + 1$
$f (x) = x + 1$ for $x > - 1$

$g (x) = x + \frac{1}{x}$ for $x > 0$

Many-one function