Question

Which of the following transitions of electrons in the hydrogen atom will emit maximum energy?

• A. $n_5\to n_4$
• B. $n_4\to n_3$
• C. $n_3\to n_2$
• D. all will emit same energy

Answer 1

Answer: (C)

$\Delta E$ for two energy levels $=21.79\left(\frac{1}{n_1^2}-\frac{1}{n_2^2}\right)J/$ atom.
Emmitted energy decreases for electron transition between two immediate states as we move to higher principle states.
Mathematically also, value of $\left(\frac{1}{n_1^2}-\frac{1}{n_2^2}\right)$ will decrease.