Which of the following statements is true about hydrogen bonding?

Question

Which of the following statements is true about hydrogen bonding? (A) Cl and N have comparable electronegativities yet there is no H-bonding in HCl because size of Cl is large (B) Intermolecular H-bonding results in decrease in m.p. and b.p.  (C) Ice has maximum density at 0° C due to H-bonding (D) KHCl2(HCl2-) exists but KHF2(HF2-) does not i exist due to lack of H-bonding in HCl.

Tardigrade Admin · Accepted Answer

For hydrogen bonding, the size of the atom should be small.

Q. Which of the following statements is true about hydrogen bonding?

$Cl$ and $N$ have comparable electronegativities yet there is no $H$ -bonding in $H Cl$ because size of $Cl$ is large

Intermolecular $H$ -bonding results in decrease in $m . p .$ and $b . p .$

Ice has maximum density at $0^{\circ} C$ due to $H$ -bonding

$KH C l_{2} (H C l_{2}^{-})$ exists but $KH F_{2} (H F_{2}^{-})$ does not i exist due to lack of $H$ -bonding in $H Cl$ .

For hydrogen bonding, the size of the atom should be small.

Q. Which of the following statements is true about hydrogen bonding?

Cl and N have comparable electronegativities yet there is no H-bonding in HCl because size of Cl is large

Intermolecular H-bonding results in decrease in m.p. and b.p.

Ice has maximum density at 0∘C due to H-bonding

KHCl2​(HCl2−​) exists but KHF2​(HF2−​) does not i exist due to lack of H-bonding in HCl.

For hydrogen bonding, the size of the atom should be small.

$Cl$ and $N$ have comparable electronegativities yet there is no $H$ -bonding in $H Cl$ because size of $Cl$ is large

Intermolecular $H$ -bonding results in decrease in $m . p .$ and $b . p .$

Ice has maximum density at $0^{\circ} C$ due to $H$ -bonding

$KH C l_{2} (H C l_{2}^{-})$ exists but $KH F_{2} (H F_{2}^{-})$ does not i exist due to lack of $H$ -bonding in $H Cl$ .