ClO4− does not disproportionate because in this oxo anion chlorine is present in its highest oxidation state (+7). The disproportionation reactions for the other three oxo anions of chlorine are as follows : 3C+1lO−→2C-1l−+Cl+5O3− 6C+3lO2−hv4C+5lO3−+2C-1l− 4C+5lO3−→C-1l−+3C+7lO4−