Which of the following solutions would produce maximum elevation in boiling point?

Question

Which of the following solutions would produce maximum elevation in boiling point? (A) 0.1 M BaCl2  (B) 0.1 M KCl  (C) 0.1 M glucose (D) 0.1 M sucrose

Tardigrade Admin · Accepted Answer

Colligative property propto number of particles. Elevation of boiling point will be maximum for 0.1 MB Bl 2 solution because it will produce maximum ion, (i.e., 3) in the solution. BaCl 2 arrow Ba 2++2 Cl -

Q. Which of the following solutions would produce maximum elevation in boiling point?

$0.1 M B a C l_{2}$

$0.1 M K Cl$

0.1 M glucose

0.1 M sucrose

Colligative property $\propto$ number of particles.
Elevation of boiling point will be maximum for $0.1 MB B l_{2}$ solution because it will produce maximum ion, (i.e., 3) in the solution.
$B a C l_{2} \to B a^{2 +} + 2 C l^{-}$

Q. Which of the following solutions would produce maximum elevation in boiling point?

0.1MBaCl2​

0.1MKCl

0.1 M glucose

0.1 M sucrose

Colligative property ∝ number of particles. Elevation of boiling point will be maximum for 0.1MBBl2​ solution because it will produce maximum ion, (i.e., 3) in the solution. BaCl2​→Ba2++2Cl−

$0.1 M B a C l_{2}$

$0.1 M K Cl$

Colligative property $\propto$ number of particles.
Elevation of boiling point will be maximum for $0.1 MB B l_{2}$ solution because it will produce maximum ion, (i.e., 3) in the solution.
$B a C l_{2} \to B a^{2 +} + 2 C l^{-}$