Which of the following solutions will exhibit highest boiling point?

Question

Which of the following solutions will exhibit highest boiling point? (A) 0.01 M Na 2 SO 4( aq ) (B) 0.01 M KNO 3( aq ) (C) 0.015 M urea ( aq ) (D) 0.015 M glucose ( aq )

Tardigrade Admin · Accepted Answer

Molecules having maximum number of ions will have maximum value of boiling point. In the given options, 0.01 M Na 2 SO 4 contains maximum number of ions. So, 0.01 M Na 2 SO 4 has highest boiling point.

Q. Which of the following solutions will exhibit highest boiling point?

$0.01 M N a_{2} S O_{4} (a q)$

$0.01 M K N O_{3} (a q)$

$0.015 M$ urea $(a q)$

$0.015 M$ glucose $(a q)$

Molecules having maximum number of ions will have maximum value of boiling point. In the given options, $0.01 M N a_{2} S O_{4}$ contains maximum number of ions. So, $0.01 M N a_{2} S O_{4}$ has highest boiling point.

Q. Which of the following solutions will exhibit highest boiling point?

0.01MNa2​SO4​(aq)

0.01MKNO3​(aq)

0.015M urea (aq)

0.015M glucose (aq)

Molecules having maximum number of ions will have maximum value of boiling point. In the given options, 0.01MNa2​SO4​ contains maximum number of ions. So, 0.01MNa2​SO4​ has highest boiling point.

$0.01 M N a_{2} S O_{4} (a q)$

$0.01 M K N O_{3} (a q)$

$0.015 M$ urea $(a q)$

$0.015 M$ glucose $(a q)$

Molecules having maximum number of ions will have maximum value of boiling point. In the given options, $0.01 M N a_{2} S O_{4}$ contains maximum number of ions. So, $0.01 M N a_{2} S O_{4}$ has highest boiling point.