Which of the following solutions has the highest normality?

Question

Which of the following solutions has the highest normality? (A) 8 g of KOH /liter (B) 6 g of NaOH/100 mL (C) 1 g phosphoric acid/liter (D) 0.5 M H 2 SO 4

Tardigrade Admin · Accepted Answer

N = (6 × 1000/40 × 100) = 15 N

Q. Which of the following solutions has the highest normality?

8 g of KOH /liter

6 g of NaOH/100 mL

1 g phosphoric acid/liter

$0.5 M H_{2} S O_{4}$

$N = \frac{6 \times 1000}{40 \times 100} = 15 N$

Q. Which of the following solutions has the highest normality?

8 g of KOH /liter

6 g of NaOH/100 mL

1 g phosphoric acid/liter

0.5MH2​SO4​

N=40×1006×1000​=15N

$0.5 M H_{2} S O_{4}$

$N = \frac{6 \times 1000}{40 \times 100} = 15 N$