Question

Which of the following salts undergoes hydrolysis?

• A. $K_{2}S{O}_4$
• B. $\text{KCl}$
• C. $NaN{O}_3$
• D. $C{H}_{3}COONa$

Answer 1

Answer: (D)

$K_{2}S{O}_4,KCl$ and $NaN{O}_3$ are the salts of strong acids and strong basis, so they do not undergo hydrolysis. $C{H}_{3}COOK$ is salt of weak acid, $C{H}_{3}COOH$ and strong basic NaOH, so it hydrolyses to give basic solution (i.e., $pH>7$ )
${\left(\text{CH}\right)}_{\text{3}}{\left(\text{COO}\right)}^{-}\text{K}\text{+}\text{HOH}\to \underset{\left(\text{weak}\text{acid}\right)}{{\left(\text{CH}\right)}_{\text{3}}\text{COOH}}\text{+}\underset{\left(\text{strong}\text{base}\right)}{\mathrm{KOH}}$