Which of the following salt is most effective in the coagulation of an arsenious sulphide sol?

Question

Which of the following salt is most effective in the coagulation of an arsenious sulphide sol? (A) AlCl3 (B) NaCl (C) BaCl2 (D) Na3PO4

Tardigrade Admin · Accepted Answer

Arsenious sulphide is -ve charged colloid. Hence, cation having maximum positive charge will be most effective for coagulation. (Hardy Schulz rule) Al3 +>Ba2 +>Na+ (coagulating power)

Q. Which of the following salt is most effective in the coagulation of an arsenious sulphide sol?

$A lC l_{3}$

$N a Cl$

$B a C l_{2}$

$N a_{3} P O_{4}$

Arsenious sulphide is -ve charged colloid. Hence, cation having maximum positive charge will be most effective for coagulation. (Hardy Schulz rule)
$A l^{3 +} > B a^{2 +} > N a^{+}$ (coagulating power)

Q. Which of the following salt is most effective in the coagulation of an arsenious sulphide sol?

AlCl3​

NaCl

BaCl2​

Na3​PO4​

Arsenious sulphide is -ve charged colloid. Hence, cation having maximum positive charge will be most effective for coagulation. (Hardy Schulz rule) Al3+>Ba2+>Na+ (coagulating power)

$A lC l_{3}$

$N a Cl$

$B a C l_{2}$

$N a_{3} P O_{4}$

Arsenious sulphide is -ve charged colloid. Hence, cation having maximum positive charge will be most effective for coagulation. (Hardy Schulz rule)
$A l^{3 +} > B a^{2 +} > N a^{+}$ (coagulating power)