Which of the following represents the correct order of the acidity in the given compounds?

Question

Which of the following represents the correct order of the acidity in the given compounds? (A) FCH 2 COOH > CH 3 COOH > BrCH 2 COOH > ClCH 2 COOH (B) BrCH 2 COOH > ClCH 2 COOH > FCH 2 COOH > CH 3 COOH (C) FCH 2 COOH > ClCH 2 COOH > BrCH 2 COOH > CH 3 C O OH (D) CH 3 COOH > BrCH 2 COOH > ClCH 2 COOH > FCH 2 COOH

Tardigrade Admin · Accepted Answer

Electron withdrawing substituent (like halogen,

N O_{2}, C_{6} H_{5}

etc.) would disperse the negative charge and hence stabilise the carboxylate ion and thus increases acidity of the parent acid. On the other hand, electron-releasing substituents would intensify the negative charge, destabilise the carboxylate ion and thus decrease acidity of the parent acid.
Electronegativity decreases in order

F > Cl > Br

and hence-I effect also decreases in the same order, therefore the correct option is

[FC H_{2} COO H > ClC H_{2} COO H > B r C H_{2} COO H > C H_{3} COO H]

Q. Which of the following represents the correct order of the acidity in the given compounds?

$FC H_{2} COO H > C H_{3} COO H > B r C H_{2} COO H >$ $ClC H_{2} COO H$

$B r C H_{2} COO H > ClC H_{2} COO H > FC H_{2} COO H >$ $C H_{3} COO H$

$FC H_{2} COO H > ClC H_{2} COO H > B r C H_{2} COO H > C H_{3} COO H$

$C H_{3} COO H > B r C H_{2} COO H > ClC H_{2} COO H >$ $FC H_{2} COO H$

Q. Which of the following represents the correct order of the acidity in the given compounds?

FCH2​COOH>CH3​COOH>BrCH2​COOH> ClCH2​COOH

BrCH2​COOH>ClCH2​COOH>FCH2​COOH> CH3​COOH

FCH2​COOH>ClCH2​COOH>BrCH2​COOH>CH3​COOH

CH3​COOH>BrCH2​COOH>ClCH2​COOH> FCH2​COOH

$FC H_{2} COO H > C H_{3} COO H > B r C H_{2} COO H >$ $ClC H_{2} COO H$

$B r C H_{2} COO H > ClC H_{2} COO H > FC H_{2} COO H >$ $C H_{3} COO H$

$FC H_{2} COO H > ClC H_{2} COO H > B r C H_{2} COO H > C H_{3} COO H$

$C H_{3} COO H > B r C H_{2} COO H > ClC H_{2} COO H >$ $FC H_{2} COO H$