Applying sine rule in △ABC, we get sinAa=sinBb=sin(π−A−B)c=2R
or sinAa=sinBb=sin(A+B)c=2R
(a) If we know a,sinA,sinB, we can find b,c, and the value of angles A,B, and C.
(b) Using a,b,c, we can find ∠A,∠B,∠C using the cosine law.
(c) a,sinB,R are given, so sinA,b and hence sin(A+B) and then C can be found.
(d) If we know a,sinA,R, then we know only the ratio sinBb or sin(A+B)c; we cannot determine the values of b,c,sinB,sinC separately. Therefore, the triangle cannot be determined in this case.