Which of the following particle will describe the smallest circle when projected with same velocity perpendicular to magnetic field ?

Question

Which of the following particle will describe the smallest circle when projected with same velocity perpendicular to magnetic field ? (A) Electron (B) proton (C) He+ (D) Li+

Tardigrade Admin · Accepted Answer

We know that, radius of circular path (R)=(mv/qB) Here, v, q and B are same. So, R propto m. The mass of electron is minimum. So, electron will describe the smallest circle when projected with same velocity perpendicular to magnetic field

Q. Which of the following particle will describe the smallest circle when projected with same velocity perpendicular to magnetic field ?

Electron

proton

$H e^{+}$

$L i^{+}$

We know that,
radius of circular path $(R) = \frac{m v}{qB}$
Here, $v, q$ and $B$ are same.
So, $R \propto m$ .
The mass of electron is minimum. So, electron will describe the smallest circle when projected with same velocity perpendicular to magnetic field