Which of the following orders is correct for the bond dissociation energy of O2, O2-, O2- and O22-?

Question

Which of the following orders is correct for the bond dissociation energy of O2, O2-, O2- and O22-? (A) O2+ > O2 > O2- > O2-2 (B) O2+ > O2 < O2- < O22- (C) O2+ < O2 < O2- < O22- (D) O2+ > O2 > O2- > O22-

Tardigrade Admin · Accepted Answer

The bond order are as follows. O2 = 2 ; O2+ = 2.5 ; O2- = 1.5; O22- = 1

Q. Which of the following orders is correct for the bond dissociation energy of $O_{2}, O_{2}^{-}, O_{2}^{-}$ and $O_{2}^{2 -}$ ?

$O_{2}^{+} > O_{2} > O_{2}^{-} > O_{2}^{2 -}$

$O_{2}^{+} > O_{2} < O_{2}^{-} < O_{2}^{2 -}$

$O_{2}^{+} < O_{2} < O_{2}^{-} < O_{2}^{2 -}$

$O_{2}^{+} > O_{2} > O_{2}^{-} > O_{2}^{2 -}$

The bond order are as follows.
$O_{2} = 2; O_{2}^{+} = 2.5; O_{2}^{-} = 1.5; O_{2}^{2 -} = 1$

Q. Which of the following orders is correct for the bond dissociation energy of O2​,O2−​,O2−​ and O22−​?

O2+​>O2​>O2−​>O22−​

O2+​>O2​<O2−​<O22−​

O2+​<O2​<O2−​<O22−​

O2+​>O2​>O2−​>O22−​

The bond order are as follows. O2​=2;O2+​=2.5;O2−​=1.5;O22−​=1

Q. Which of the following orders is correct for the bond dissociation energy of $O_{2}, O_{2}^{-}, O_{2}^{-}$ and $O_{2}^{2 -}$ ?

$O_{2}^{+} > O_{2} > O_{2}^{-} > O_{2}^{2 -}$

$O_{2}^{+} > O_{2} < O_{2}^{-} < O_{2}^{2 -}$

$O_{2}^{+} < O_{2} < O_{2}^{-} < O_{2}^{2 -}$

$O_{2}^{+} > O_{2} > O_{2}^{-} > O_{2}^{2 -}$

The bond order are as follows.
$O_{2} = 2; O_{2}^{+} = 2.5; O_{2}^{-} = 1.5; O_{2}^{2 -} = 1$