Which of the following is the expression of Raoults law? ( p= vapour pressure of pure solvent, ps= vapour pressure of the solution)

Question

Which of the following is the expression of Raoults law? ( p= vapour pressure of pure solvent, ps= vapour pressure of the solution) (A)  (p-ps/p)=(n/n+N)  (B)  (ps-p/p)=(N/N+n)  (C)  (p-ps/ps)=(N/N-n)  (D)  (ps-p/ps)=(N-n/N)

Tardigrade Admin · Accepted Answer

According to Raoults law, for non-volatile solute, the relative lowering of vapour pressure of a solution is equal to the mole fraction of the solute. (p-ps/p)=(n/n+N)

Q. Which of the following is the expression of Raoults law? ( $p =$ vapour pressure of pure solvent, $p_{s} =$ vapour pressure of the solution)

$\frac{p - p _{s}}{p} = \frac{n}{n + N}$

$\frac{p _{s} - p}{p} = \frac{N}{N + n}$

$\frac{p - p _{s}}{p _{s}} = \frac{N}{N - n}$

$\frac{p _{s} - p}{p _{s}} = \frac{N - n}{N}$

According to Raoults law, for non-volatile solute, the relative lowering of vapour pressure of a solution is equal to the mole fraction of the solute. $\frac{p - p _{s}}{p} = \frac{n}{n + N}$

Q. Which of the following is the expression of Raoults law? ( p= vapour pressure of pure solvent, ps​= vapour pressure of the solution)

pp−ps​​=n+Nn​

pps​−p​=N+nN​

ps​p−ps​​=N−nN​

ps​ps​−p​=NN−n​