Which of the following is the correct order of increasing field strength of ligands to form coordination compounds ?

Question

Which of the following is the correct order of increasing field strength of ligands to form coordination compounds ? (A) SCN- < F- < C2O42- < CN- (B) SCN- < F- < CN- < C2O42- (C) F- < SCN- < C2O42- < CN- (D) CN- < C2O42- < SCN- < F-

Tardigrade Admin · Accepted Answer

Arrangement o f different ligands in increasing order of field strength called spectrochemical series is as follows: I-< SCN-< Cl-< S2-< F-< OH-< C2O2-4< H2O< NH3< CN-< CO

Q. Which of the following is the correct order of increasing field strength of ligands to form coordination compounds ?

$SC N^{-} < F^{-} < C_{2} O_{4}^{2 -} < C N^{-}$

$SC N^{-} < F^{-} < C N^{-} < C_{2} O_{4}^{2 -}$

$F^{-} < SC N^{-} < C_{2} O_{4}^{2 -} < C N^{-}$

$C N^{-} < C_{2} O_{4}^{2 -} < SC N^{-} < F^{-}$

Arrangement o f different ligands in increasing order of field strength called spectrochemical series is as follows:
$I^{-} < SC N^{-} < C l^{-} < S^{2 -} < F^{-} < O H^{-} < C_{2} O_{4}^{2 -} < H_{2} O < N H_{3} < C N^{-} < CO$

Q. Which of the following is the correct order of increasing field strength of ligands to form coordination compounds ?

SCN−<F−<C2​O42−​<CN−

SCN−<F−<CN−<C2​O42−​

F−<SCN−<C2​O42−​<CN−

CN−<C2​O42−​<SCN−<F−

Arrangement o f different ligands in increasing order of field strength called spectrochemical series is as follows: I−<SCN−<Cl−<S2−<F−<OH−<C2​O42−​<H2​O<NH3​<CN−<CO

$SC N^{-} < F^{-} < C_{2} O_{4}^{2 -} < C N^{-}$

$SC N^{-} < F^{-} < C N^{-} < C_{2} O_{4}^{2 -}$

$F^{-} < SC N^{-} < C_{2} O_{4}^{2 -} < C N^{-}$

$C N^{-} < C_{2} O_{4}^{2 -} < SC N^{-} < F^{-}$

Arrangement o f different ligands in increasing order of field strength called spectrochemical series is as follows:
$I^{-} < SC N^{-} < C l^{-} < S^{2 -} < F^{-} < O H^{-} < C_{2} O_{4}^{2 -} < H_{2} O < N H_{3} < C N^{-} < CO$