Q.
Which of the following is not correct with respect to bond length of the species?
3395
194
KEAMKEAM 2011Chemical Bonding and Molecular Structure
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Solution:
Greater the bond order, shorter is the bond length. ∴Bondorder∝bondlength1 (i) Electronic configurations and bond orders of C2 and C22− ions:
EC of C2=KKσ2s2,σ∗2s2,π2px2,π2py2
Bond order =21(6−2)=2
EC of C22−=KKσ2s2,σ∗2s2,π2px2,π2py2,σ2pz2
Bond order =21(8−2)=3 ∴ The order of bond lengths: B2+>B2
(ii) Electronic configurations and bond orders of B2+ and B2 EC of B2=KKσ2s2,σ∗2s2,π2px1,π2px1,π2p1y
Bond order =21(4−2)=1
EC of B2+=KKσ2s2,σ∗2s2,π2px1
Bond order =21(3−2)=21 ∴ The order of bond lengths: B2+>B2
(iii) Electronic configurations and bond orders of Li2 and Li2+ EC of Li2=KKσ2s2
Bond order =21(2−0)=1 EC of Li2+=KKσ2s1
Bond order =21(1−0)=21 ∴ The order of bond lengths: Li2+>Li2 (iv) Electronic configurations and bond orders of N2 and N2+ EC of N2=KKσ2s2,σ∗2s2,π2px2,π2py2,σ2pz2 Bond order =21(8−2)=3
EC of N2+=KKσ2s2,σ∗2s2,π2px2,π2py2,σ2pz1
Bond order =21(7−2)=2.5 ∴ The order of bond lengths =N2+>N2
(v) Electronic configurations and bond orders of O2 and O2− : EC of O2=KKσ2s2,σ∗2s2,σ2pz2,π2px2 π2py2,π∗2px1,π∗2py1
Bond order =21(8−4)=2 EC of O2−=KKσ2s2,σ∗2s2,π2pz2,π2px2,π2py2, π∗2px2,π∗2py1
Bond order =21(8−5)=1.5 ∴ The correct order of bond lengths =O2−>O2