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NTA AbhyasNTA Abhyas 2020Chemical Bonding and Molecular Structure
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Solution:
In (C) and (D) there is lp−bp repulsions. The size of methyl group is greater than F , hence (B) experience greater repulsion than (A).
according to bent rule more electronegative atom occupy axial position because axial position has more p- character, so 2 F atoms placed at axial first then rest of F atom occupy equatorial position.