Q.
Which of the following is incorrect statement about OSF4?
1971
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NTA AbhyasNTA Abhyas 2020Chemical Bonding and Molecular Structure
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Solution:
In OSF4, BP = 5, LP = 0 and hence the hybridization is sp3 d and shape is trigonal-bipyramidal.
Distortion in geometry due to presence of S=O (Bond) equatorially. S-atom does not contain any lone pair electrons. Distortion in geometry due to presence of S=O (Bond) equatorially. S-atom does not contain any lone pair electrons.