Which of the following is incorrect statement about OSF4 ?

Question

Which of the following is incorrect statement about OSF4 ? (A) S atom has sp3d hybridization (B) OSF4 has distorted trigonal bipyramidal shape. (C) O atom is present at equatorial position. (D) There is no lone pair on S.

Tardigrade Admin · Accepted Answer

In OSF 4, BP =5, LP =0 and hence the hybridization is sp 3 d and shape is trigonal-bipyramidal. <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-unvga6bk0ummhfwp.jpg" /> Distortion in geometry due to presence of S=O (Bond) equatorial. S-atom does not contain any lone pair electrons. Hence, there will be no distortion in geometry.

Q. Which of the following is incorrect statement about $OS F_{4}$ ?

S atom has $s p^{3} d$ hybridization

$OS F_{4}$ has distorted trigonal bipyramidal shape.

O atom is present at equatorial position.

There is no lone pair on S.

In $OS F_{4}, BP = 5, L P = 0$ and hence the hybridization is $s p^{3} d$ and shape is trigonal-bipyramidal.

Distortion in geometry due to presence of S=O (Bond) equatorial. S-atom does not contain any lone pair electrons. Hence, there will be no distortion in geometry.

Q. Which of the following is incorrect statement about OSF4​ ?

S atom has sp3d hybridization

OSF4​ has distorted trigonal bipyramidal shape.