Question

Which of the following is incorrect statement about $OSF_4$ ?

• A. S atom has $sp^3d$ hybridization
• B. $OSF_4$ has distorted trigonal bipyramidal shape.
• C. O atom is present at equatorial position.
• D. There is no lone pair on S.

Answer 1

Answer: (B)

In $OSF _4, BP =5, LP =0$ and hence the hybridization is $sp ^3 d$ and shape is trigonal-bipyramidal.

Distortion in geometry due to presence of S=O (Bond) equatorial. S-atom does not contain any lone pair electrons. Hence, there will be no distortion in geometry.