Which of the following is diamagnetic in nature?

Question

Which of the following is diamagnetic in nature? (A)  Co3+ , octahedral complex with weak field ligands (B)  Co3+ , octahedral complex with strong field ligands (C)  Co2+ in tetrahedral complex (D)  Co2+ in square planar complex

Tardigrade Admin · Accepted Answer

Co 3+=[ Ar ] 3 d6 4 s0 In the presence of strong field ligands, pairing occurs. Thus, Co 3+ (in presence =[ Ar ] of strong (no unpaired electrons) field ligand) Thus, it is diamagnetic in nature. (Note: Co 2+ always contains an unpaired electron.)

Q. Which of the following is diamagnetic in nature?

$C o^{3 +}$ , octahedral complex with weak field ligands

$C o^{3 +}$ , octahedral complex with strong field ligands

$C o^{2 +}$ in tetrahedral complex

$C o^{2 +}$ in square planar complex

$C o^{3 +} = [A r] 3 d^{6} 4 s^{0}$ In the presence of strong field ligands, pairing occurs.
Thus, $C o^{3 +}$ (in presence $= [A r]$
of strong (no unpaired electrons) field ligand) Thus, it is diamagnetic in nature.
(Note: $C o^{2 +}$ always contains an unpaired electron.)

Q. Which of the following is diamagnetic in nature?

Co3+ , octahedral complex with weak field ligands

Co3+ , octahedral complex with strong field ligands

Co2+ in tetrahedral complex

Co2+ in square planar complex

Co3+=[Ar]3d64s0 In the presence of strong field ligands, pairing occurs. Thus, Co3+ (in presence =[Ar] of strong (no unpaired electrons) field ligand) Thus, it is diamagnetic in nature. (Note: Co2+ always contains an unpaired electron.)

$C o^{3 +}$ , octahedral complex with weak field ligands

$C o^{3 +}$ , octahedral complex with strong field ligands

$C o^{2 +}$ in tetrahedral complex

$C o^{2 +}$ in square planar complex

$C o^{3 +} = [A r] 3 d^{6} 4 s^{0}$ In the presence of strong field ligands, pairing occurs.
Thus, $C o^{3 +}$ (in presence $= [A r]$
of strong (no unpaired electrons) field ligand) Thus, it is diamagnetic in nature.
(Note: $C o^{2 +}$ always contains an unpaired electron.)