Question

Which of the following is correct order regarding ionic size?

• A. $H^{-}>I^{-}>B{r}^{-}>C{l}^{-}>F^{-}$
• B. $I^{-}>B{r}^{-}>C{l}^{-}>F^{-}>H^{-}$
• C. $I^{-}>H^{-}>B{r}^{-}>C{l}^{-}>F^{-}$
• D. $I^{-}>B{r}^{-}>C{l}^{-}>H^{-}>F^{-}$

Answer 1

Answer: (C)

Basically as we go down the group number of shells are increased and due to which radius of ions is increased. So order of radius of halogen anions will be: $I^{-}>B{r}^{-}>C{l}^{-}>F^{-}$ and if we compare hydrogen ion with this anions then order will be $I^{-}>H^{-}>B{r}^{-}>C{l}^{-}>F^{-}$