Question

Which of the following have linear structure?
I. $SnC{l}_2$
II. $Be{F}_2$
III. $S{O}_2$
IV. $\stackrel{+}{N}{O}_2$
V. $C_2{H}_2$

• A. I, II, IV
• B. II, IV, V
• C. II, III, IV
• D. I, V , V

Answer 1

Answer: (B)

Structure of :

I.$SnC{l}_{2}Sn$ have $4$ valence electrons, which form two sigma ( $\sigma$ ) bonds and have one lone pair $(lp)$ of electrons over $Sn$ atom, thus have $V$-shaped structure.

II. $Be{F}_{2}F-Be-F$
Linear Be have two valence electrons bonded with $2F$ -atoms, thus has no $lp$ of electrons and have linear structure.


III. $S{O}_2$ Sulphur $(S)$ have six $(6)$ valence electrons, out of which sulphur can form one coordinate sigma, one simple $(\sigma )$ and one $pi(\pi )$ bond with $O$-atoms having one $lp$ of electrons over sulphur atom. Thus, $S{O}_2$ have bent structure.

IV. $\stackrel{+}{N}{O}_2$ Nitrogen in $N{O}_2$ have four $(4)$ electrons in its outermost shell, which are involved in formation of


one coordinate, one simple sigma and one $\pi$ - bond with $O$-atoms. It has no $lp$ of electrons over $N$-atom, thus have linear structure.

V . $C_2{H}_2\underset{\text{(Linear)}}{H-C\equiv C-H}$

Carbon has four valence electrons which forms two sigma bonds with two $H$ -atoms one by each $C$ -atom) and one sigma bond between two $C$-atoms. It also forms two $pi(\pi )$ bonds between two $C$-atoms to complete its octate. Thus, has linear structure.