Question

Which of the following have identical bond order?
(I) $C{N}^{-}$ (II) $O_2^{-}$ (III) $N{O}^{+}$ (IV) $C{N}^{+}$

• A. I, III
• B. I, II
• C. II, IV
• D. I, II, III

Answer 1

Answer: (A)

Isoelectronic species have same bond order.
$C{N}^{-}=6+7+1=14$ electrons,
$O_2^{-}=8+8+1=17$ electrons,
$N{O}^{+}=7+8-1=14$ electrons,
$C{N}^{+}=6+7-1=12$ electrons.