Question

which of the following has $p\pi -d\pi$ bonding?

• A. $N{O}_3^{-}$
• B. $S{O}_3^{2-}$
• C. $B{O}_3^{3-}$
• D. $C{O}_3^{2-}$

Answer 1

Answer: (B)

In $S{O}_3^{2-}$ d-orbital of $S$ atom overlaps with $p$-orbital of $O$-atom to form a $\pi$-bond hence, $S{O}_3^{2-}$ has $p\pi -d\pi$ bonding.