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Question
Chemistry
Which of the following given below can liberate Br2 from KBr? F2,Cl2,I2 and Conc. text textH2SO4
Q. Which of the following given below can liberate
B
r
2
from KBr?
F
2
,
C
l
2
,
I
2
and
C
o
n
c
.
H
2
S
O
4
2661
226
NTA Abhyas
NTA Abhyas 2020
The p-Block Elements - Part2
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A
F
2
,
C
l
2
,
I
2
and
C
o
n
c
.
H
2
S
O
4
33%
B
C
l
2
,
I
2
and
C
o
n
c
.
H
2
S
O
4
0%
C
F
2
,
C
l
2
,
I
2
0%
D
F
2
,
C
l
2
and
C
o
n
c
.
H
2
S
O
4
67%
Solution:
I
2
cannot liberate
B
r
2
from KBr, since
I
2
is weaker oxidant than
B
r
2
.
F
2
and
C
l
2
, being stronger oxidants than
B
r
2
, can liberate
B
r
2
from KBr.
F
2
+
2
K
B
r
→
2
K
F
+
B
r
2
C
l
2
+
2
K
B
r
→
2
K
Cl
+
B
r
2
Reaction of conc.
H
2
S
O
4
with KBr forms HBr. HBr is a strong reducing agent so it reduces
H
2
S
O
4
to form a mixture of
S
O
2
and
B
r
2
.
K
B
r
+
H
2
S
O
4
→
H
B
r
+
KH
S
O
4
KH
S
O
4
+
K
B
r
→
H
B
r
+
K
2
S
O
4
HBr so formed reduces
H
2
S
O
4
.
H
2
S
O
4
+
2
H
B
r
→
S
O
2
+
2
H
2
O
+
B
r
2