Q.
Which of the following functions from Z into Z are bijective?
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Relations and Functions - Part 2
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Solution:
f(x)=x3 cannot be onto as range of f={..., −27, −8, −1, 0, 1, 8, 27, ...}=Z f(x)=2x+1 is also not onto as Rf={..., −3, −1, 1, 3, ...}=Z f(x)=x2+1 is not one-one as f(x)=f(−x)=x2+1
And f(x)=x+2 is one-one as f(x1)=f(x2) ⇒x1=x2
and it is onto also [∵Rf=Z}
Hence, f(x)=(x+2) is bijective.