Question

Which of the following figure shown below is correct regarding the steady flow of a non viscous liquid?

• A.
• B.
• C.
• D.

Answer 1

Answer: (A)

By equation of continuity
$Av$ = constant $\dots \left(i\right)$
where $A$ is the area of cross-section of tube and $v$ is the velocity of flow
From (i) it is clear that, when area of cross section of tube is less, the velocity of the liquid flow is more
So the velocity of liquid flow of a constriction of tube is more than the other portion of tube
By Bernoullis theorem $P+\frac{1}{2}\rho v^2$ = constant
Therefore if $v$ is more, $P$ is less and vice versa