Which of the following expression represents the energy of electron in a hydrogen atom?

Question

Which of the following expression represents the energy of electron in a hydrogen atom? (A) E = (2π2me4/h2) (1/n2) (B) E = (4π2me2/h2) (1/n2) (C) E = -(2π2me4/h2) (1/n2) (D) E = -(4π2me2/h2) (1/n2)

Tardigrade Admin · Accepted Answer

The energy of an electron in the nth orbit of hydrogen is given by En=(-2π2me4/n2h2)

Q. Which of the following expression represents the energy of electron in a hydrogen atom?

$E = \frac{2 π ^{2} m e ^{4}}{h ^{2}} \frac{1}{n ^{2}}$

$E = \frac{4 π ^{2} m e ^{2}}{h ^{2}} \frac{1}{n ^{2}}$

$E = - \frac{2 π ^{2} m e ^{4}}{h ^{2}} \frac{1}{n ^{2}}$

$E = - \frac{4 π ^{2} m e ^{2}}{h ^{2}} \frac{1}{n ^{2}}$

The energy of an electron in the $n^{t h}$ orbit of hydrogen is given by $E_{n} = \frac{- 2 π ^{2} m e ^{4}}{n ^{2} h ^{2}}$

Q. Which of the following expression represents the energy of electron in a hydrogen atom?

E=h22π2me4​n21​

E=h24π2me2​n21​

E=−h22π2me4​n21​

E=−h24π2me2​n21​

The energy of an electron in the nth orbit of hydrogen is given by En​=n2h2−2π2me4​

$E = \frac{2 π ^{2} m e ^{4}}{h ^{2}} \frac{1}{n ^{2}}$

$E = \frac{4 π ^{2} m e ^{2}}{h ^{2}} \frac{1}{n ^{2}}$

$E = - \frac{2 π ^{2} m e ^{4}}{h ^{2}} \frac{1}{n ^{2}}$

$E = - \frac{4 π ^{2} m e ^{2}}{h ^{2}} \frac{1}{n ^{2}}$

The energy of an electron in the $n^{t h}$ orbit of hydrogen is given by $E_{n} = \frac{- 2 π ^{2} m e ^{4}}{n ^{2} h ^{2}}$