24Cr[Ar]3d54s1Cr2+3d44s0=4 unpaired electrons Mn[Ar]3d54s2Mn2+3d54s0=5 unpairedelectrons Fe[Ar]3d64s2Fe2+3d64s0=4 unpaired electrons
Since both Cr2+ and Fe2+ contain 4 unpaired electrons, the correct option is C.
Option D is also correct because density order given is not correct.