Which of the following conditions are correct for real solutions showing negative deviation from Raoult's law?

Question

Which of the following conditions are correct for real solutions showing negative deviation from Raoult's law? (A) Δ HMix < 0 ; Δ VMix > 0 (B) Δ HMix > 0 ; Δ VMix > 0 (C) Δ HMix > 0 ; Δ VMix < 0 (D) Δ HMix < 0 ; Δ VMix < 0

Tardigrade Admin · Accepted Answer

Conditions that are correct for real solutions showing negative deviation from Raoult's law are as follows

p_{A} < p_{A}^{\circ} x_{A} and p_{B} < p_{A}^{\circ} X_{B}

Δ_{mix} H = - ve

Dissolution is exothermic heating decreases solubility

Δ_{mixing} V = -

ve

Q. Which of the following conditions are correct for real solutions showing negative deviation from Raoult's law?

$Δ H_{M i x} < 0; Δ V_{M i x} > 0$

$Δ H_{M i x} > 0; Δ V_{M i x} > 0$

$Δ H_{M i x} > 0; Δ V_{M i x} < 0$

$Δ H_{M i x} < 0; Δ V_{M i x} < 0$

Conditions that are correct for real solutions showing negative deviation from Raoult's law are as follows
$p_{A} < p_{A}^{\circ} x_{A} and p_{B} < p_{A}^{\circ} X_{B}$
$Δ_{mix} H = - ve$
Dissolution is exothermic heating decreases solubility
$Δ_{mixing} V = -$ ve

Q. Which of the following conditions are correct for real solutions showing negative deviation from Raoult's law?

ΔHMix​<0;ΔVMix​>0

ΔHMix​>0;ΔVMix​>0

ΔHMix​>0;ΔVMix​<0

ΔHMix​<0;ΔVMix​<0

Conditions that are correct for real solutions showing negative deviation from Raoult's law are as follows pA​<pA​∘xA​ and pB​<pA∘​XB​ Δmix​H=− ve Dissolution is exothermic heating decreases solubility Δmixing ​V=− ve

$Δ H_{M i x} < 0; Δ V_{M i x} > 0$

$Δ H_{M i x} > 0; Δ V_{M i x} > 0$

$Δ H_{M i x} > 0; Δ V_{M i x} < 0$

$Δ H_{M i x} < 0; Δ V_{M i x} < 0$

Conditions that are correct for real solutions showing negative deviation from Raoult's law are as follows
$p_{A} < p_{A}^{\circ} x_{A} and p_{B} < p_{A}^{\circ} X_{B}$
$Δ_{mix} H = - ve$
Dissolution is exothermic heating decreases solubility
$Δ_{mixing} V = -$ ve