Which of the following compounds is square planar and does not have any unpaired electron?

Question

Which of the following compounds is square planar and does not have any unpaired electron? (A) Ni ( CO )4 (B) [ Ni ( H 2 O )6]2+ (C) [ NiCl 4]2- (D) .[ Ni ( CN )4)]2-

Tardigrade Admin · Accepted Answer

In [ Ni ( CN )4]2-, oxidation state of Ni =+2 Ni 2+ arrow 3 d8 <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/fb6de6ea53a2ab8e05dae3385faddcd8-.png" /> d s p2 hybridisation results in square planar geometry, with no unpaired electrons.

Q. Which of the following compounds is square planar and does not have any unpaired electron?

$N i (CO)_{4}$

$[N i (H_{2} O)_{6}]^{2 +}$

$[N i C l_{4}]^{2 -}$

$[N i (CN)_{4})]^{2 -}$

In $[N i (CN)_{4}]^{2 -},$ oxidation state of $N i = + 2$

$N i^{2 +} \to 3 d^{8}$

$d s p^{2}$ hybridisation results in square planar geometry, with no unpaired electrons.

Q. Which of the following compounds is square planar and does not have any unpaired electron?

Ni(CO)4​

[Ni(H2​O)6​]2+

[NiCl4​]2−

[Ni(CN)4​)]2−

In [Ni(CN)4​]2−, oxidation state of Ni=+2 Ni2+→3d8 dsp2 hybridisation results in square planar geometry, with no unpaired electrons.

$N i (CO)_{4}$

$[N i (H_{2} O)_{6}]^{2 +}$

$[N i C l_{4}]^{2 -}$

$[N i (CN)_{4})]^{2 -}$

In $[N i (CN)_{4}]^{2 -},$ oxidation state of $N i = + 2$

$N i^{2 +} \to 3 d^{8}$

$d s p^{2}$ hybridisation results in square planar geometry, with no unpaired electrons.