Which of the following compound displays geometrical isomerism?

Question

Which of the following compound displays geometrical isomerism? (A) H 2 C = CHBr (B) H 2 C = CBr 2 (C) ( Cl ) HC = CH ( Br ) (D) Br 2 C = CCl 2

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-diyq5iypbwx7jyf1.jpg" /> Each end of double bond must contain different atoms (or) groups to show geometrical isomerism. There should be restricted rotation and planarity in the molecule to show geometrical isomerism. Geometrical isomers are named as cis and trans isomers.

Q. Which of the following compound displays geometrical isomerism?

$H_{2} C = C H B r$

$H_{2} C = CB r_{2}$

$(Cl) H C = C H (B r)$

$B r_{2} C = CC l_{2}$

Each end of double bond must contain different atoms (or) groups to show geometrical isomerism. There should be restricted rotation and planarity in the molecule to show geometrical isomerism. Geometrical isomers are named as cis and trans isomers.

Q. Which of the following compound displays geometrical isomerism?

H2​C=CHBr

H2​C=CBr2​

(Cl)HC=CH(Br)

Br2​C=CCl2​

Each end of double bond must contain different atoms (or) groups to show geometrical isomerism. There should be restricted rotation and planarity in the molecule to show geometrical isomerism. Geometrical isomers are named as cis and trans isomers.

$H_{2} C = C H B r$

$H_{2} C = CB r_{2}$

$(Cl) H C = C H (B r)$

$B r_{2} C = CC l_{2}$