Which of the following bond angle is related to NO 2 molecule: 120°, 109°, 115°, 180°, 134° (Fill your answer as sum of digits.)

Question

Which of the following bond angle is related to NO 2 molecule: 120°, 109°, 115°, 180°, 134° (Fill your answer as sum of digits.) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Hybridization of nitrogen atom in N O2 is s p2. In nitrogen dioxide there are two sigma bonds and one single electron. The geometry of molecule is bent and bond angle is 134°, which is more than ideal bond angle of s p2 120°. Thus answer is 1+3+4=8

Q. Which of the following bond angle is related to $N O_{2}$ molecule:
$12 0^{\circ}, 10 9^{\circ}, 11 5^{\circ}, 18 0^{\circ}, 13 4^{\circ}$
(Fill your answer as sum of digits.)

Hybridization of nitrogen atom in $N O_{2}$ is $s p^{2}$ .
In nitrogen dioxide there are two sigma bonds and one single electron. The geometry of molecule is bent and bond angle is $13 4^{\circ}$ , which is more than ideal bond angle of $s p^{2} 12 0^{\circ}$ .
Thus answer is $1 + 3 + 4 = 8$

Q. Which of the following bond angle is related to NO2​ molecule: 120∘,109∘,115∘,180∘,134∘ (Fill your answer as sum of digits.)

Hybridization of nitrogen atom in NO2​ is sp2. In nitrogen dioxide there are two sigma bonds and one single electron. The geometry of molecule is bent and bond angle is 134∘, which is more than ideal bond angle of sp2120∘. Thus answer is 1+3+4=8

Q. Which of the following bond angle is related to $N O_{2}$ molecule:
$12 0^{\circ}, 10 9^{\circ}, 11 5^{\circ}, 18 0^{\circ}, 13 4^{\circ}$
(Fill your answer as sum of digits.)

Hybridization of nitrogen atom in $N O_{2}$ is $s p^{2}$ .
In nitrogen dioxide there are two sigma bonds and one single electron. The geometry of molecule is bent and bond angle is $13 4^{\circ}$ , which is more than ideal bond angle of $s p^{2} 12 0^{\circ}$ .
Thus answer is $1 + 3 + 4 = 8$