Which of following ratio is correct for the production of one molecule of glucose through 6 rounds of Calvin cycle?

Question

Which of following ratio is correct for the production of one molecule of glucose through 6 rounds of Calvin cycle? (A) CO2 - 1, ATP - 2, NADPH2 - 2 (B) CO2 - 6, ATP - 18, NADPH2 - 12 (C) CO2 - 6, ATP - 12, NADPH2 - 18 (D) CO2 - 5, ATP - 6, NADPH2 - 9

Tardigrade Admin · Accepted Answer

6 CO 2, 18 ATP and 12 NADPH 2 are required for the production of one molecule of glucose, 18 ADP and 12 NADP through 6 rounds of Calvin cycle.

Q. Which of following ratio is correct for the production of one molecule of glucose through 6 rounds of Calvin cycle?

$C O_{2} - 1, A TP - 2, N A D P H_{2} - 2$

$C O_{2} - 6, A TP - 18, N A D P H_{2} - 12$

$C O_{2} - 6, A TP - 12, N A D P H_{2} - 18$

$C O_{2} - 5, A TP - 6, N A D P H_{2} - 9$

$6 C O_{2}, 18 A TP$ and $12 N A D P H_{2}$ are required for the production of one molecule of glucose, $18 A D P$ and 12 NADP through 6 rounds of Calvin cycle.

Q. Which of following ratio is correct for the production of one molecule of glucose through 6 rounds of Calvin cycle?

CO2​−1,ATP−2,NADPH2​−2

CO2​−6,ATP−18,NADPH2​−12

CO2​−6,ATP−12,NADPH2​−18

CO2​−5,ATP−6,NADPH2​−9

6CO2​,18ATP and 12NADPH2​ are required for the production of one molecule of glucose, 18ADP and 12 NADP through 6 rounds of Calvin cycle.

$C O_{2} - 1, A TP - 2, N A D P H_{2} - 2$

$C O_{2} - 6, A TP - 18, N A D P H_{2} - 12$

$C O_{2} - 6, A TP - 12, N A D P H_{2} - 18$

$C O_{2} - 5, A TP - 6, N A D P H_{2} - 9$

$6 C O_{2}, 18 A TP$ and $12 N A D P H_{2}$ are required for the production of one molecule of glucose, $18 A D P$ and 12 NADP through 6 rounds of Calvin cycle.