Question

Which o f the following facts about the complex $[Cr(N{H}_3{)}_6]C{l}_3$ is wrong?

• A. The complex involves $d^{2}s{p}^3$ hybridization and is octahedral in shape
• B. The complex is paramagnetic
• C. The complex is an outer orbital complex
• D. The complex gives white precipitate with silver nitrate solution.

Answer 1

Answer: (C)

In $[Cr(N{H}_3{)}_6{]}^{3+}$, $Cr$ exists as $C{r}^{3+}$ ion. The outer orbital electronic configuration of $Cr$ is $3d^{3}4S^0$. The orbital diagram is represented by

Here, X indicates lone pair of $N{H}_3$ donated to Cr. Hence,
(a) $d^2-s{p}^3$ hybridization, octahedral. Thus, correct.
(b) There are three unpaired electrons, hence paramagnetic. Thus, correct.
(c) $d^2-s{p}^3$ inner orbital complex, thus incorrect.
(d) Due to ionizable $C{l}^{-}$ ions, white precipitate with $AgN{O}_3$, thus correct.