Which is the correct statement if N2 is added at equilibrium condition?

Question

Which is the correct statement if N2 is added at equilibrium condition? (A) The equilibrium will shift to forward direction because according to second law of thermodynamics, the entropy must increase in the direction of spontaneous reaction. (B) The condition for equilibrium is GN2+3 GH2=2 GN H2 where G is Gibbs free energy per mole of the gaseous species measured at that partial pressure. The condition of equilibrium is unaffected by the use of catalyst, which increases the rate of both the forward and backward reactions to the same extent. (C) The catalyst will increase the rate of forward reaction by α and that of backward reaction by β. (D) Catalyst will not alter the rate of either of the reaction.

Tardigrade Admin · Accepted Answer

The change in Gibbs free energy is given by Δ G (reaction) =Δ G (products) -Δ G (reactants) Also, catalyst only speeds up the reaction without affecting the equilibrium conditions.

Q. Which is the correct statement if $N_{2}$ is added at equilibrium condition?

The equilibrium will shift to forward direction because according to second law of thermodynamics, the entropy must increase in the direction of spontaneous reaction.

The catalyst will increase the rate of forward reaction by $α$ and that of backward reaction by $β$ .

Catalyst will not alter the rate of either of the reaction.

The change in Gibbs free energy is given by
$Δ G$ (reaction) $= Δ G$ (products) $- Δ G$ (reactants)
Also, catalyst only speeds up the reaction without affecting the equilibrium conditions.

Q. Which is the correct statement if N2​ is added at equilibrium condition?

The equilibrium will shift to forward direction because according to second law of thermodynamics, the entropy must increase in the direction of spontaneous reaction.

The catalyst will increase the rate of forward reaction by α and that of backward reaction by β.

Catalyst will not alter the rate of either of the reaction.

The change in Gibbs free energy is given by ΔG (reaction) =ΔG (products) −ΔG (reactants) Also, catalyst only speeds up the reaction without affecting the equilibrium conditions.

Q. Which is the correct statement if $N_{2}$ is added at equilibrium condition?

The catalyst will increase the rate of forward reaction by $α$ and that of backward reaction by $β$ .

The change in Gibbs free energy is given by
$Δ G$ (reaction) $= Δ G$ (products) $- Δ G$ (reactants)
Also, catalyst only speeds up the reaction without affecting the equilibrium conditions.