Which is the correct relationship :

Question

Which is the correct relationship : (A) E1 of H=1 / 2 E2 of He +=1 / 3 E 3 of Li 2+=1 / 4 E 4 of Be 3+ (B) E 1( H )= E 2( He +)= E 3( Li 2+)= E 4( Be 3+) (C) E 1( H )=2 E 2( He +)=3 E 3( Li 2+)= 4 E 4( Be 3+) (D) No relation

Tardigrade Admin · Accepted Answer

E 1( H )=-13.6 × (12/12)=-13.6 eV ; E 2( He +)=-13.6 × (22/22)=-13.6 eV E 3( Li 2+)=-13.6 × (32/32)=-13.6 eV ; E 4( Be 3+)=-13.6 × (42/42)=-13.6 eV ∴ E 1( H )= E 2( He +) = E 3( Li 2+)= E 4( Be 3+)

Q. Which is the correct relationship :

$E_{1}$ of $H = 1/2 E_{2}$ of $H e^{+} = 1/3 E_{3}$ of $L i^{2 +} = 1/4 E_{4}$ of $B e^{3 +}$

$E_{1} (H) = E_{2} (H e^{+}) = E_{3} (L i^{2 +}) =$ $E_{4} (B e^{3 +})$

$E_{1} (H) = 2 E_{2} (H e^{+}) = 3 E_{3} (L i^{2 +}) =$ $4 E_{4} (B e^{3 +})$

No relation

Q. Which is the correct relationship :

E1​ of H=1/2E2​ of He+=1/3E3​ of Li2+=1/4E4​ of Be3+

E1​(H)=E2​(He+)=E3​(Li2+)= E4​(Be3+)

E1​(H)=2E2​(He+)=3E3​(Li2+)= 4E4​(Be3+)

No relation

E1​(H)=−13.6×1212​=−13.6eV; E2​(He+)=−13.6×2222​=−13.6eV E3​(Li2+)=−13.6×3232​=−13.6eV; E4​(Be3+)=−13.6×4242​=−13.6eV ∴E1​(H)=E2​(He+) =E3​(Li2+)=E4​(Be3+)

$E_{1}$ of $H = 1/2 E_{2}$ of $H e^{+} = 1/3 E_{3}$ of $L i^{2 +} = 1/4 E_{4}$ of $B e^{3 +}$

$E_{1} (H) = E_{2} (H e^{+}) = E_{3} (L i^{2 +}) =$ $E_{4} (B e^{3 +})$

$E_{1} (H) = 2 E_{2} (H e^{+}) = 3 E_{3} (L i^{2 +}) =$ $4 E_{4} (B e^{3 +})$