Which is incorrect statement regarding B2H6 ?

Question

Which is incorrect statement regarding B2H6 ? (A) It is a strong reducing agent (B) On heating, it gives amorphous boron (C) It is a planar molecule (D) With excess (CH3)3N, it undergoes symmetrical cleavage

Tardigrade Admin · Accepted Answer

Four Ht and two B atoms lie in the same plane while two bridging H atoms (Hb) lie in a plane perpendicular to the rest of the molecule. Thus, B2H6 is not a planar molecule.

Q. Which is incorrect statement regarding $B_{2} H_{6}$ ?

It is a strong reducing agent

On heating, it gives amorphous boron

It is a planar molecule

With excess $(C H_{3})_{3} N$ , it undergoes symmetrical cleavage

Four $H_{t}$ and two $B$ atoms lie in the same plane while two bridging H atoms $(H_{b})$ lie in a plane perpendicular to the rest of the molecule. Thus, $B_{2} H_{6}$ is not a planar molecule.

Q. Which is incorrect statement regarding B2​H6​ ?