Which is correct relation in between -(d C/d t),-(d n/d t), and -(d P/d t) where C, n, P, represents concentration, mole, and pressure terms for gaseous phase reactant A ( g ) arrow Product:

Question

Which is correct relation in between -(d C/d t),-(d n/d t), and -(d P/d t) where C, n, P, represents concentration, mole, and pressure terms for gaseous phase reactant A ( g ) arrow Product: (A) -(d C/d t) and =-(1/V) (d n/d t)=-(1/R T) (d P/d t) (B) -(d C/d t)=-(d n/d t)=-(d P/d t) (C) -(d C/d t)=-(R T/V) (d n/d t)=-(d P/d t) (D) all of these.

Tardigrade Admin · Accepted Answer

Rate =-[(d C/d t)]=[-(d n/d t)] (1/V) ∵ C=(n/v) Also C=(P/R T) ∴ -[(d C/d t)]=-(1/R T)[(d p/d t)]

Q. Which is correct relation in between $- \frac{d C}{d t}, - \frac{d n}{d t}$ , and $- \frac{d P}{d t}$ where $C, n, P$ , represents concentration, mole, and pressure terms for gaseous phase reactant $A (g) \to$ Product:

$- \frac{d C}{d t}$ and $= - \frac{1}{V} \frac{d n}{d t} = - \frac{1}{RT} \frac{d P}{d t}$

$- \frac{d C}{d t} = - \frac{d n}{d t} = - \frac{d P}{d t}$

$- \frac{d C}{d t} = - \frac{RT}{V} \frac{d n}{d t} = - \frac{d P}{d t}$

all of these.

Rate $= - [\frac{d C}{d t}] = [- \frac{d n}{d t}] \frac{1}{V}$
$∵ C = \frac{n}{v}$
Also $C = \frac{P}{RT}$
$∴ - [\frac{d C}{d t}] = - \frac{1}{RT} [\frac{d p}{d t}]$

Q. Which is correct relation in between −dtdC​,−dtdn​, and −dtdP​ where C,n,P, represents concentration, mole, and pressure terms for gaseous phase reactant A(g)→ Product:

−dtdC​ and =−V1​dtdn​=−RT1​dtdP​

−dtdC​=−dtdn​=−dtdP​

−dtdC​=−VRT​dtdn​=−dtdP​