Question

Which has square planar geometry?

• A. $\left[Pt{\left(N{H}_3\right)}_{2}C{l}_2\right]$
• B. ${\left[Ni(CN{)}_4\right]}^{2-}$
• C. Both (a) and (b)
• D. None of these

Answer 1

Answer: (C)

Oxidation state of $Pt$ in $\left[Pt{\left(N{H}_3\right)}_{2}C{l}_2\right]=+2$

$ds{p}^2$ -hybridisation leads to square planar geometry.
Oxidation state of $Ni$ in ${\left[Ni(CN{)}_4\right]}^{2-}=+2$

$ds{p}^2$ -hybridisation leads to square planar geometry.