Which combination of reagents used in the indicated order will give m-nitropropylbenzene from benzene?

Question

Which combination of reagents used in the indicated order will give m-nitropropylbenzene from benzene? (A) 1)conc. HNO3 / conc. H2 SO4 2)CH3 CH2 CH2 / AlCl3 (B) 1) CH3 CH2 CH2 CllAlCl3 2) conc. HNO3/ conc. H2 SO4 (C) 1) CH3 CH2 COCllAlCl3 2) conc. HNO3 conc. H2SO4 3)H2 NNH2 / NaOH (D) 1) conc. HNO3 / conc. H2 SO4 2) CH3 CH2 COCllAlCl3 3) H2 NN H2 / NaOH

Tardigrade Admin · Accepted Answer

Correct answer is (c) 1) CH3 CH2 COCllAlCl3 2) conc. HNO3 conc. H2SO4 3)H2 NNH2 / NaOH

Q. Which combination of reagents used in the indicated order will give m-nitropropylbenzene from benzene?

1) $co n c . H N O_{3} / co n c . H_{2} S O_{4}$
2) $C H_{3} C H_{2} C H_{2} / A lC l_{3}$

1) $C H_{3} C H_{2} C H_{2} Cll A lC l_{3}$
2) $co n c . H N O_{3} / co n c . H_{2} S O_{4}$

1) $C H_{3} C H_{2} COCll A lC l_{3}$
2) $co n c . H N O_{3} co n c . H_{2} S O_{4}$
$3) H_{2} NN H_{2} / N a O H$

1) $co n c . H N O_{3} / co n c . H_{2} S O_{4}$
2) $C H_{3} C H_{2} COCll A lC l_{3}$
3) $H_{2} NN H_{2} / N a O H$

Correct answer is (c) 1) $C H_{3} C H_{2} COCll A lC l_{3}$
2) $co n c . H N O_{3} co n c . H_{2} S O_{4}$
$3) H_{2} NN H_{2} / N a O H$

Q. Which combination of reagents used in the indicated order will give m-nitropropylbenzene from benzene?

1)conc.HNO3​/conc.H2​SO4​ 2)CH3​CH2​CH2​/AlCl3​

1) CH3​CH2​CH2​CllAlCl3​ 2) conc.HNO3​/conc.H2​SO4​

1) CH3​CH2​COCllAlCl3​ 2) conc.HNO3​conc.H2​SO4​ 3)H2​NNH2​/NaOH

1) conc.HNO3​/conc.H2​SO4​ 2) CH3​CH2​COCllAlCl3​ 3) H2​NNH2​/NaOH

Correct answer is (c) 1) CH3​CH2​COCllAlCl3​ 2) conc.HNO3​conc.H2​SO4​ 3)H2​NNH2​/NaOH

1) $co n c . H N O_{3} / co n c . H_{2} S O_{4}$
2) $C H_{3} C H_{2} C H_{2} / A lC l_{3}$

1) $C H_{3} C H_{2} C H_{2} Cll A lC l_{3}$
2) $co n c . H N O_{3} / co n c . H_{2} S O_{4}$

1) $C H_{3} C H_{2} COCll A lC l_{3}$
2) $co n c . H N O_{3} co n c . H_{2} S O_{4}$
$3) H_{2} NN H_{2} / N a O H$

1) $co n c . H N O_{3} / co n c . H_{2} S O_{4}$
2) $C H_{3} C H_{2} COCll A lC l_{3}$
3) $H_{2} NN H_{2} / N a O H$

Correct answer is (c) 1) $C H_{3} C H_{2} COCll A lC l_{3}$
2) $co n c . H N O_{3} co n c . H_{2} S O_{4}$
$3) H_{2} NN H_{2} / N a O H$