Question

Which arrangement of $3\Omega$ resistors will give a total resistance of $7\Omega$ ?

• A.
• B.
• C.
• D.

Answer 1

Answer: (D)

Three resistors of $3\Omega$ each in parallel will give $\left(\frac{1}{\frac{1}{3}+\frac{1}{3}+\frac{1}{3}}\right)=1\Omega$
$R_{eq}=3+1+3=7\Omega$.